In the first one, I don’t think you can go from a^2 - b^2 to (a+b)(a-b).
On the second one, I don’t think you can go from (Pi+3)(Pi-3) to Pi^2-9.
On the third one, I don’t know enough about imaginary numbers to figure it out. They’re probably doing something with squaring i that doesn’t work, or something.
Anyways, all of these are most likely wrong. It’s summer. :)
1. line: (a+b)(a-b) = b(a-b)..a-b is zero
the line is not determined by what zero is multiplied by.
it doesnt not matter what else is on the line bc both
sides are multiplied by zero.
2. When you have two unknown is a single equation.
there are an infinite set of solutions. So u can get
one of the variables…to basically equal anything
Unless there are mathmatical restrictions based
on the given equation(in this case..there aren’t).
3. When you take a squareroot of anything it results in
a plus or minus (+/-) number. Ex: sqrt(9)= (+/-)3.
So if that was done correctly the final answer would
be (+/-)1=(+/1)1. The mistake was assuming the
positive answer to both the square roots.
Hey! These are really nice and deceivingly astonishing problems. How did you arrive at these conclusions or from where did you get these ideas. Really great!!
In the first one, I don’t think you can go from
a^2 - b^2to(a+b)(a-b).On the second one, I don’t think you can go from
(Pi+3)(Pi-3)toPi^2-9.On the third one, I don’t know enough about imaginary numbers to figure it out. They’re probably doing something with squaring
ithat doesn’t work, or something.Anyways, all of these are most likely wrong. It’s summer. :)
Hehe. The steps you said for the first two work. That formula works for everything all the time. ;)
Well… obviously not.
1. line: (a+b)(a-b) = b(a-b)..a-b is zero
the line is not determined by what zero is multiplied by.
it doesnt not matter what else is on the line bc both
sides are multiplied by zero.
2. When you have two unknown is a single equation.
there are an infinite set of solutions. So u can get
one of the variables…to basically equal anything
Unless there are mathmatical restrictions based
on the given equation(in this case..there aren’t).
3. When you take a squareroot of anything it results in
a plus or minus (+/-) number. Ex: sqrt(9)= (+/-)3.
So if that was done correctly the final answer would
be (+/-)1=(+/1)1. The mistake was assuming the
positive answer to both the square roots.
im a nerd :-\
tj
You are absolutely correct! I couldn’t figure out the last one for the longest time.
Hey! These are really nice and deceivingly astonishing problems. How did you arrive at these conclusions or from where did you get these ideas. Really great!!
I didn’t read the other comments.
Well… since a=b… and you’re also cancelling out a-b with a-b… and division with 0 is impossible. :/
I got these from EEtimes, a computer-related magazine. I guess I should be giving credit, but they didn’t write it either.
Aarohi, you got the first one right!